解答
136
SQL文(クエリ)
WITH master AS (
SELECT
order_id AS orders
, SUM(revenue) AS sum_rev
FROM
sample.sales
GROUP BY
order_id
)
SELECT
COUNT(DISTINCT orders) AS count_orders
, SUM(sum_rev) AS sum_rev
, SUM(sum_rev) / COUNT(DISTINCT orders) AS average_order_value
FROM
master



