解答

142

SQL文(クエリ)

WITH master AS (
  SELECT
    user_id
    , SUM(revenue) AS sum_rev
  FROM
    sample.sales
  GROUP BY
    user_id
)
SELECT
  gender
  , is_premium
  , SUM(sum_rev) AS sum_rev
FROM
  master
  LEFT JOIN sample.customers
  USING
    (user_id)
WHERE
  prefecture = "東京"
GROUP BY
  gender
  , is_premium
ORDER BY
  gender
  , is_premium DESC

結果テーブル

結果テーブル

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