解答
183
SQL文(クエリ)
WITH master AS ( SELECT cid , session_count , COUNT(*) AS pv FROM sample.web_log GROUP BY cid , session_count ) SELECT ROUND(pageviews / sessions, 1) AS pv_per_session FROM ( SELECT ( SELECT SUM(pv) AS pageviews FROM master ) AS pageviews , ( SELECT COUNT(*) FROM master ) AS sessions )