解答
205
SQL文(クエリ)
WITH master AS ( SELECT user_id , COUNT(DISTINCT order_id) AS orders , COUNT(DISTINCT product_id) AS items , SUM(revenue) AS total_revenue FROM sample.sales GROUP BY user_id ) , master2 AS ( SELECT user_id , MAX(sum_rev) AS biggest_order FROM ( SELECT user_id , order_id , SUM(revenue) AS sum_rev FROM sample.sales GROUP BY user_id , order_id ) GROUP BY user_id ) SELECT user_id , orders , total_revenue , biggest_order , items FROM ( SELECT * FROM master JOIN master2 USING (user_id) ) WHERE orders >= 7 ORDER BY user_id