解答
214
SQL文(クエリ)
SELECT
gender
, ROUND(AVG(age), 1) AS avg_age
, MAX(med_age) AS median_age
FROM
(
SELECT
*
, PERCENTILE_CONT(age, 0.5) OVER (PARTITION BY gender)
AS med_age
FROM
(
SELECT
CASE gender
WHEN 1 THEN "男性"
WHEN 2 THEN "女性"
ELSE NULL
END AS gender
, DATE_DIFF("2019-12-31", birthday, YEAR) AS age
FROM
sample.customers
WHERE
birthday IS NOT NULL
)
)
GROUP BY
gender



