解答
223
SQL文(クエリ)
WITH master AS ( SELECT user_id , SUM(revenue) AS sum_rev FROM sample.sales GROUP BY user_id ) SELECT * , ROUND(accum_sum_rev_by_bucket / ( SELECT SUM(sum_rev) FROM master ), 2) AS accum_rev_percentage FROM ( SELECT rev_bucket , sum_rev_by_bucket , SUM(sum_rev_by_bucket) OVER (ORDER BY rev_bucket) AS accum_sum_rev_by_bucket FROM ( SELECT rev_bucket , SUM(sum_rev) AS sum_rev_by_bucket FROM ( SELECT * , NTILE(5) OVER (ORDER BY sum_rev DESC) AS rev_bucket FROM master ) GROUP BY rev_bucket ) )