解答
226
SQL文(クエリ)
WITH master17 AS ( SELECT user_id , sum_rev17 , NTILE(10) OVER (ORDER BY sum_rev17 DESC) AS rev_bucket17 FROM ( SELECT user_id , SUM(revenue) AS sum_rev17 FROM sample.sales WHERE FORMAT_DATETIME("%Y", date_time) = "2017" GROUP BY user_id ) ) , master18 AS ( SELECT user_id , sum_rev18 , NTILE(10) OVER (ORDER BY sum_rev18 DESC) AS rev_bucket18 FROM ( SELECT user_id , SUM(revenue) AS sum_rev18 FROM sample.sales WHERE FORMAT_DATETIME("%Y", date_time) = "2018" GROUP BY user_id ) ) SELECT user_id FROM master17 INNER JOIN master18 USING (user_id) WHERE rev_bucket17 = 1 AND rev_bucket18 = 1