解答
198
SQL文(クエリ)
WITH master AS ( SELECT user_id , gender , product_name , revenue FROM sample.sales LEFT JOIN sample.products USING (product_id) LEFT JOIN sample.customers USING (user_id) ) SELECT product_name , SUM(rev_female) AS sum_rev_female , SUM(rev_female) / MAX(ttl_rev) AS percent_rev_female FROM ( SELECT product_name , IF(gender = 2, revenue, 0) AS rev_female , ( SELECT SUM(revenue) FROM sample.sales ) AS ttl_rev FROM master ) GROUP BY 1 ORDER BY 2 DESC LIMIT 3